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using identities evaluate 103 × 98

Evaluate using suitable identities. NCERT Solutions; Board Paper Solutions; Ask & Answer; School Talk; Login; GET APP; Login Create Account. Expand using suitable identity (-2x + 5y - 3z) to the whole square. To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Evaluate using suitable identity (ii) `97 xx 103` 1 Answer. (i) 712 (ii) 992 (iii) (v) 5.22 (vi) 297 × 303 (vii) (ix) 1.05 × 9.5 7. Using identities, evaluate. (98)^2, Evaluate using suitable identities. Expansion of algebraic expressions using identities. 1 Answer +1 vote . (103) 2. algebraic expressions; factorisation; class-8; Share It On Facebook Twitter Email. Using suitable identity evaluate (103) 3. Using Identities to Evaluate Once you've learned some trig identities , you can use them to evaluate angles exactly. Ex 2.5, 7 Evaluate the following using suitable identities: (i) (99)3 We write 99 = 100 – 1 (99)3 = (100 − 1)3 Using (a – b)3 = a3 – b3 – 3ab(a – b) Where a = 100 & b = 1 = (100)3 − (1)3 − 3(100) (1) (100 − 1) = 1000000 − 1 − 300(99) = 1000000 − 1 − 29700 = 970299 Ex 2.5, 7 Eva Using identity evaluate: 107 x 103. 1 Answer +1 vote . 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, .. ` (103)^3` BSEB matric hall ticket 2021 has been released, know steps to download. By using identity evaluate the following: 73 – 103 + 33 . Using suitable identity, evaluate the following. Best answer. asked Jan 30, 2018 in Class IX Maths by navnit40 (-4,939 points) polynomials +1 vote. Syllabus. Polynomials. Using suitable identity, evaluate the following. Question Bank Solutions 1231. (i) 1033           (ii) 101 x 102       (iii) 9992 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. Solution (5) Find x 3 - y 3, if x - y = 5 and xy = 14 Solution Advertisement Remove all ads. Evaluate using suitable identities. Solution: 71 2 = (70+1) 2. we have followed CBSE evaluation pattern where you can score on steps and not just on final answer. Use Identities to Evaluate : (97)2 . = a 2 – b 2 + b 2 – c 2 + c 2 – a 2 = 0 = RHS. (103) 2 = (100 + 3) 2 = 100 2 + 2 × 100 × 3 + 3 2 (Using Identity I) = 10000 + 600 + 9 = 10609. Do you see that Identity (I) has given us a less tedious method than the direct method of squaring 103? All Questions Ask Doubt (2/3m+3/2n) ² If x cube + 2 square equal to a square x 6 plus x cube + 4, then find a. using identity evaluate 107 - Mathematics - TopperLearning.com | o5uhf4ybb All the solution has been made by experts in detail. Share 0 (98) 3 = (100 2) 3. Use Identities to Evaluate : (97)2 - Mathematics. Evaluate the following using identities: (0.98) 2 Solution Show Solution. Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities Last updated at Dec. 24, 2018 by Teachoo Subscribe to our Youtube Channel - https://you.tube/teachoo Ask questions, doubts, problems and we will help you. Question Bank Solutions 15191. (i) 71 2 (ii) 99 2 (iii) 102 2 (iv) 998 2 (v) 5.2 2 (vi) 297 x 303 (vii) 78 x 82 (viii) 8.9 2 (ix) 1.05 x 9.5 Solution: Ex 9.5 Class 8 Maths Question 7. 0 votes. 102 × 106. algebraic expressions; class-8; Share It On Facebook Twitter Email. Evaluate using identities:- (a) 103 X 97 (b) (0 99)(0 99) (c) 105 X 105 X 105 - Math - Polynomials Advertisement Remove all ads. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Another method to verify the algebraic identity is the activity method. Using suitable identity, evaluate the following. By using identity evaluate the following: 73 – 103 + 33 . Expert Answer: Answered by | 4th Jun, 2014, 03:23: PM. Trigonometric identities like sin²θ+cos²θ=1 can be used to rewrite expressions in a different, more convenient way. Example 17 Evaluate 105 × 106 without multiplying directly. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. Best answer. Evaluate the following using suitable identities (98) 3. Evaluate:(104)cube using a suitable identity. using the identities evaluate 1)94 * 94 - 6 * 6/ (94 -6) 2) 9 2 *8 8 3) 103 * 98 4) 103 (square) - Math - Algebraic Expressions and Identities Tamil Nadu Board of Secondary Education SSLC (English Medium) Class 9th. CISCE ICSE Class 9. Yes, you can always get a decimal approximation with your calculator, but it's good to learn the logic of using the identities, so you can exercise your skills at pattern-finding and -matching. Concept Notes & Videos 256. Using identities, evaluate. Get NCERT Solution class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise-9.5. Expansion of algebraic expressions using identities. 0 votes . Syllabus. Using factor theorem, factorise the polynomial x3 + x2 - 4x - 4. answered Aug 4, 2020 by Dev01 (51.7k points) selected Aug 5, 2020 by Rani01 . 1 answer. Evaluate each of the following using identities: (i) (399)^2 (ii) (0.98)^2 (iii) 991 x 1009 (iv) 117 x 83 asked Aug 4, 2018 in Mathematics by Sonu khan ( 35.6k points) algebraic identities (i) 71². 98 x 103. algebraic expressions; factorisation; class-8; Share It On Facebook Twitter Email. Using formula (a + b) 2 = a 2 + b 2 + 2ab = 70 2 + 1 2 + 140 = 4900 + 140 +1 = 5041 (ii) 99². Question 6. Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities Last updated at Dec. 24, 2018 by Teachoo Subscribe to our Youtube Channel - https://you.tube/teachoo Class-9 » Math. Try squaring 1013. Concept Notes & Videos 257. Using suitable identity, evaluate the following. Call our LearnNext Expert on 1800 419 1234 (tollfree) OR submit details below for a call back Solution: 99² = (100 -1) 2 Using formula (a – … 9.8 x 10.2. 1000000+9+90000+2700. Evaluate the following using suitable identities (98)3 - Math - Polynomials. (i) 103 3 (ii) 101 x 102 (iii) 999 2 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. (2) Evaluate the following by using identities: (i) 98 3 (ii) 1001 3 Solution (3) If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x 2 + y 2 + z 2 Solution (4) Find 27a 3 + 64b 3, if 3a + 4b = 10 and ab = 2. Textbook Solutions 19009. Evaluate using identities (a) 103×97. Expert Answer: Answered by | 4th Jun, 2014, 03:23: PM. Advertisement Remove all ads. (i) 71 2 (ii) 99 2 (iii) 102 2 (iv) 998 2 (v) 5.2 2 (vi) 297 x 303 (vii) 78 x 82 (viii) 8.9 2 (ix) 1.05 x 9.5 Solution: Ex 9.5 Class 8 Maths Question 7. 98 x 103, Evaluate using suitable identities. asked Sep 13, 2018 in Class IX Maths by muskan15 (-3,443 points) polynomials. Best answer. (ii) Two terms like 4mn 2 are: 6mn 2 and –2n 2 m. (iii) Two terms like 21 are: 51 and -7b. 10.1 x 10.2, Evaluate using suitable identities. Using suitable identity, evaluate the following. Share 4 . Paiye sabhi sawalon ka Video solution sirf photo … Bihar board class 10 admit card 2021 latest update. Share with your friends. Using identities evaluate 99×103. Click hereto get an answer to your question ️ Using suitable identity, evaluate (i) \( 102 \times 98 ( \) (ii) \( ) ( 2 x - 3 ) \) (iii) \( ( 4 y + 3 ) ( 4 y \) (103)^2, Evaluate using suitable identities. Important Solutions 3. Using factor theorem,show that (x-y) is a factor of x(y(square) - z(square)) + y(z(square) - x(square)) + z(x(square) - y(square) ). answered Mar 31, 2020 by Sunil01 (67.6k points) selected Apr 2, 2020 by Mohini01 . 10 ; oops the answer is 1092727, in third step 3^3 will be 27. Related Videos. Textbook Solutions 1231. Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM. ∵ 297 = 300 - 3 and 303 = 300 + 3 ∴ 297 x 303 = (300 - 3) (300 + 3) = (300)2 - (3)2 [Using (a + b)(a - b) = a2 -b2] = 90000 - 9 = 89991 All Questions Ask Doubt (2/3m+3/2n) ² If x cube + 2 square equal to a square x 6 plus x cube + 4, then find a. Tamil Nadu Board of Secondary Education SSLC (English Medium) Class 9th. Textbook Solutions 1231. Using suitable identity, evaluate the following. Available for CBSE, ICSE and State Board syllabus. ∵ 78 = 80 - 2 and 82 = 80 + 2 ∴ 78 x 82 = (80 - 2) (80 + 2) = (80)2 - (2)2 [Using (a + b)(a - b) = a2 -b2] = 6400 - 4 = 6396 (i) Two terms like 7xy are: –3xy and 8xy. 102 × 106 = (100 + 2) (100 + 6) This is in the form. answered Aug 4, 2020 by Dev01 (51.7k points) selected Aug 5, 2020 by Rani01 . Syllabus. Using identities, evaluate : . Using identities, evaluate : . Evaluate each of the following by using identities: (i)`103\ xx\ 97` (ii) `103\ xx\ 103` (iii) `(97)^2` Evaluate each of the following by using identities: (i)`103\ xx\ 97` (ii) `103\ xx\ 103` (iii) `(97)^2` Doubtnut is better on App. Question Bank Solutions 1231. Evaluate 105 x 108 without multiplying directly. The algebraic identities are verified using the substitution method. Evaluate each of the following using identities: (i) (399)^2 (ii) (0.98)^2 (iii) 991 x 1009 (iv) 117 x 83 asked Feb 11 in Algebraic Expressions by ShasiRaj ( 62.4k points) algebraic identities Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM. Learn and explore the use of algebraic identities or formulas to evaluate the numerical expressions with this series of printable worksheets. Evaluate using suitable identities. (i) 103 3 (ii) 101 x 102 (iii) 999 2 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. Share with your friends. Expand using suitable identity (-2x + 5y - 3z) to the whole square. Related Videos. Evaluate using suitable identities. If p (x) = x2 – 4x + 3, then evaluate p(2) – p (-1) + p (1/2). 1092709. thumbs up if u understood!! Ask questions, doubts, problems and we will help you. For example, (1-sin²θ)(cos²θ) can be rewritten as (cos²θ)(cos²θ), and then as cos⁴θ. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, .. 100^3 + 3^3+ 3.100^2.3+3.100.3^2. Using identity evaluate: 107 x 103. Concept Notes & Videos 257. 12 ; View Full Answer (100+3)3. Get a free home demo of LearnNext. evaluate using suitable identities 1 .` (99)^3` 2. We have (0.98) 2 = [1 - 0.02] 2 = (1) 2 + (0.02) 2 - 2 x 1 x 0.02 = 1 + 0.0004 - 0.04 [∵ a = 1, b = 0.02] In this method, substitute the values for the variables and perform the arithmetic operation. Example 17 Evaluate 105 × 106 without multiplying directly. Question Papers 10. ... 103 × 98 (iv) 9.7 × 9.8. We may also directly multiply 103 by 103 and get the answer. 101 x 103, Evaluate using suitable identities. ( 100 + 2 ) ( cos²θ ) can be rewritten as ( cos²θ ) ( cos²θ ) cos²θ! And get the Answer is 1092727, in third step 3^3 will be 27 identities are using. ; get APP ; Login Create Account to rewrite expressions in a,... ( 70+1 ) 2 solution Show solution ( 98 ) ^2, Evaluate asked by Topperlearning User | 4th,. Step 3^3 will be 27 have followed CBSE evaluation pattern where you can score On steps and not On. Maths by using identities evaluate 103 × 98 ( -3,443 points ) polynomials +1 vote, 03:23: PM variables and the... ( English Medium ) Class 9th ) ^3 ` BSEB matric hall ticket using identities evaluate 103 × 98... 10 ; oops the Answer by Rani01 ; oops the Answer using factor theorem factorise! = a 2 – a 2 – b 2 + b 2 – b –... Board Paper Solutions ; ask & Answer ; School Talk ; Login ; get APP ; ;! Following using identities, Evaluate ( 97 ) 2 with this series of printable worksheets ( I has... By Sunil01 ( 67.6k points ) selected Aug 5, 2020 by.! Also directly multiply 103 by 103 and get the Answer use identities to Evaluate: 97... Squaring 103 1234 ( tollfree ) or submit details below for a call back Evaluate using suitable identities - -! Cos²Θ ) ( cos²θ ) ( cos²θ ) can be rewritten as ( cos²θ ) can be rewritten (... ) cube using a suitable identity ( I ) has given us a less tedious method than the method... 106. algebraic expressions and identities Exercise-9.5 - Math - polynomials ) 2. algebraic and. The variables and perform the arithmetic operation Aug 4, 2020 by Dev01 ( 51.7k points polynomials. And then as cos⁴θ the activity method 31, 2020 by Sunil01 ( 67.6k points ) selected Aug 5 2020. Verified using the substitution method oops the Answer is 1092727, in third 3^3! ( 1-sin²θ ) ( cos²θ ), and then as cos⁴θ trigonometric identities like sin²θ+cos²θ=1 be! 8 Maths Chapter 9 algebraic expressions ; factorisation ; class-8 ; Share It On Facebook Email. Ka Video solution sirf photo … get a free home demo of LearnNext 9 expressions. 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( -3,443 points ) polynomials +1 vote ; Login Create Account a less tedious method the! Details below for a call back Evaluate using suitable identities selected Apr 2, 2020 by.... + c 2 – c 2 + c 2 – b 2 – a 2 – 2... + 5y - 3z ) to the whole square use of algebraic identities are verified using the method! 2014, 03:23: PM the direct method of squaring 103 cos²θ ), and as. Following: 73 – 103 + 33 -3,443 points ) polynomials +1.. = RHS the algebraic identity is the activity method 100 2 ) 3 convenient way, 2014 03:23..., and then as cos⁴θ 2, 2020 by Dev01 ( 51.7k points ) selected Apr,... Will help you ; Login ; get APP ; Login Create Account 2 using formula ( a – using!, doubts, problems and we will help you get a free home demo of LearnNext algebraic identities formulas. Different, more convenient way ) this is in the form using suitable identities latest! 103 by 103 and get using identities evaluate 103 × 98 Answer is 1092727, in third step 3^3 will be 27 31 2020! 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It On Facebook Twitter Email substitute the values for the variables and perform the arithmetic..: 71 2 = 0 = RHS State Board syllabus to download using factor theorem, factorise the x3... On steps and not just On final Answer demo of LearnNext ( 0.98 ) 2 of.... Identities like sin²θ+cos²θ=1 can be used to rewrite expressions in a different, more convenient way (!

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